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-210+110x-6x^2=0
a = -6; b = 110; c = -210;
Δ = b2-4ac
Δ = 1102-4·(-6)·(-210)
Δ = 7060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7060}=\sqrt{4*1765}=\sqrt{4}*\sqrt{1765}=2\sqrt{1765}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(110)-2\sqrt{1765}}{2*-6}=\frac{-110-2\sqrt{1765}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(110)+2\sqrt{1765}}{2*-6}=\frac{-110+2\sqrt{1765}}{-12} $
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